Asked by Julio

2.40 L of N2, at 25 ∘C and 1.89 atm , is mixed with 2.60 L of O2, at 25 ∘C and 0.245 atm , and the mixture allowed to react. N2(g)+O2(g)→2NO(g)

How much NO, in grams, is produced?
Answered by Dr Jazz
Use ideal gas law to calculate the moles of NO produced from the given data. Apply to given reaction and be sure to consider limiting reagent concept. LR will dictate amount (moles) of product produced. Multiply mole wt of product x moles produced => gram yield
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