Question

When a 37.00 g silver spoon, initially at room temperature, is placed into 250.0mL of 90.00oC tea, it reaches a temperature of 85.00°C. The spoon will have gained ? J of thermal energy.

I got 5237.5 Joules as (mass)x(specific heat capacity)x(Temperature change)=Heat,
which was apparently incorrect.
Please note that we are NOT given the specific heat capacity of silver in this question.

Answers

the tea (water) loses the energy gained by the spoon

250.0 * (90.00 - 85.00) * 4.184


4 sig fig ... not 5 as in your answer

Related Questions