Asked by vani

in a adjoining figure,CAB is right angled triangle where AC=4cm(height),AB =3cm(base),and BC=5cm (hypotenuse),and AD is a altitude from BC .then find the length of altitude from A toBC,if its area is 6cm square.
Answered by Damon
of course the area of ABC = (1/2)(3*4) = 6 :)

also
(1/2)(AD)(5) = 6
AD = 12/5 = 2.4 cm