Asked by fiyin

calculate the specific heat capacity of the materials for which the heat supply, mass, and temperature rises are given below:
i)25200J, 0.3Kg
ii)8000J, 500g, from 20'C to 60'C
iii)9450J, 150g, from 15'C to 45'C

Answers

Answered by bobpursley
no delta Temp on i
on ii: C=8000/(500*40) in J/gC
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