Asked by lulu
2Na + 2H2O---> 2NaOH + H2
Need to find the molecules of H2
Atomic wt o Na = 23
48.7 g of Na
48.71/23 = 2.12 mols Na
2.12/2 × 24. (WHERE DOES THE 24 COME FROM) = 25.44 dm^3 H. (PLEASE EXPLAIN THIS PART) = 1.06moles
1.06mols× 6.02×10^23 avagados number=
1.204 × 10^24 molecules
I understand this except where the 24 comes from and the dm^3 parts----please explain
Thank you.
Need to find the molecules of H2
Atomic wt o Na = 23
48.7 g of Na
48.71/23 = 2.12 mols Na
2.12/2 × 24. (WHERE DOES THE 24 COME FROM) = 25.44 dm^3 H. (PLEASE EXPLAIN THIS PART) = 1.06moles
1.06mols× 6.02×10^23 avagados number=
1.204 × 10^24 molecules
I understand this except where the 24 comes from and the dm^3 parts----please explain
Thank you.
Answers
Answered by
bobpursley
the 24 is a sloppy way of doing unit conversion problems. Let me show you.
Volume of H2=molesH2*volumeH2/mole
=2.12molesNa*1moleH2/2molesNa*22.4dm^3/moleH2=1.06*22.4 dm^2 AT STP.
now, if you are not doing stp conditions, but rather using RTP, At RTP (room temperature and pressure), this volume is 24 dm3 (liters)
See why I called your calculations sloppy? without units, and conditions, it makes no sense.
Volume of H2=molesH2*volumeH2/mole
=2.12molesNa*1moleH2/2molesNa*22.4dm^3/moleH2=1.06*22.4 dm^2 AT STP.
now, if you are not doing stp conditions, but rather using RTP, At RTP (room temperature and pressure), this volume is 24 dm3 (liters)
See why I called your calculations sloppy? without units, and conditions, it makes no sense.
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