Asked by Anonymous
                Consider a box that contains 14 red balls,12 blue balls and 9 yellow balls.A ball is drawn at random and the color is noted and then put back inside the box.Then,another ball is drawn at random.Find the probability?
a.both are blue
b.both balls are yellow
c.the first is red and the second is yellow
d.the first is red and the second is blue
            
        a.both are blue
b.both balls are yellow
c.the first is red and the second is yellow
d.the first is red and the second is blue
Answers
                    Answered by
            Reiny
            
    I will assume that in each case, the first ball drawn is not returned.
prob(2 blue) = (12/35)(11/34) = ..
prob(2 yellow) = you do it
prob(red, then yellow) = (14/35)(9/34) = ...
prob(red, then yellow) = your turn again
    
prob(2 blue) = (12/35)(11/34) = ..
prob(2 yellow) = you do it
prob(red, then yellow) = (14/35)(9/34) = ...
prob(red, then yellow) = your turn again
                    Answered by
             ewf
            
     fr  esg
    
                    Answered by
            Anica 
            
    Consider a box that contains 14 red balls, 12 blue balls, and 9 yellow balls.
    
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