Asked by Darryl

The temperature at 5 am was -28 degrees F. The temperature at 2pm was 17 degreesf. If the temperature changed at a constant rate from 5am to 2pm what was the temperature at 6am?
Answered by Henry
(17-(-28))/(14-5) = 5deg./h.

T = 5deg./h * (6-5)h = 5 Degrees.

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