Asked by supersupersuper
Given that 3 to the power of -n= 0.2
find the value of (3 to the power of 4) to the power of n.
so 3^-n=0.2
find value of (3^4)^n
my working out:
1)3=n surd 0.2
2)n must be decimal number
3) cuberoot o.2=0.5848035476425733
4)so n=0.5848035476425733
5)(3^4)^0.5848035476425733=13.0643801669
6) so that answer is the value of (3^4)^n
find the value of (3 to the power of 4) to the power of n.
so 3^-n=0.2
find value of (3^4)^n
my working out:
1)3=n surd 0.2
2)n must be decimal number
3) cuberoot o.2=0.5848035476425733
4)so n=0.5848035476425733
5)(3^4)^0.5848035476425733=13.0643801669
6) so that answer is the value of (3^4)^n
Answers
Answered by
Steve
3^-n = 0.2
3^n = 1/0.2 = 5
(3^4)^n = (3^n)^4 = 5^4 = 625
3^n = 1/0.2 = 5
(3^4)^n = (3^n)^4 = 5^4 = 625
Answered by
Kruti & Priyanka
we don't trust you
Answered by
leo
not answer
Answered by
bianca
it’s 625
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