Asked by supersupersuper
Diagram:
OAZ line on top horizontal
OXB line vertical under O
BYA line diagonal from B to A to form a triangle which is OBA
In the middle of O and B there is a line to show x which is nearer to B.
In the middle of line BA there i s a line to sow Y in the middle.
Question:
OAB is a triangle.
A is the midpoint of OZ.
Y is the midpoint of AB.
X is a point on OB.
(Arrow on top of OA)OA=a
(Arrow on top of OX) OX=2b
(Arrow on top of XB) XB=b
Prove that XYZ is a straight line.
My working out:
1) I drew a line from X to Y to Z.
I actually have no idea at all after this step please help me!!
OAZ line on top horizontal
OXB line vertical under O
BYA line diagonal from B to A to form a triangle which is OBA
In the middle of O and B there is a line to show x which is nearer to B.
In the middle of line BA there i s a line to sow Y in the middle.
Question:
OAB is a triangle.
A is the midpoint of OZ.
Y is the midpoint of AB.
X is a point on OB.
(Arrow on top of OA)OA=a
(Arrow on top of OX) OX=2b
(Arrow on top of XB) XB=b
Prove that XYZ is a straight line.
My working out:
1) I drew a line from X to Y to Z.
I actually have no idea at all after this step please help me!!
Answers
Answered by
supersupersuper
Does anyone know? Please help!!
Answered by
supersupersuper
anyone? please help!!