Asked by supersupersuper
                Diagram:
OAZ line on top horizontal
OXB line vertical under O
BYA line diagonal from B to A to form a triangle which is OBA
In the middle of O and B there is a line to show x which is nearer to B.
In the middle of line BA there i s a line to sow Y in the middle.
Question:
OAB is a triangle.
A is the midpoint of OZ.
Y is the midpoint of AB.
X is a point on OB.
(Arrow on top of OA)OA=a
(Arrow on top of OX) OX=2b
(Arrow on top of XB) XB=b
Prove that XYZ is a straight line.
My working out:
1) I drew a line from X to Y to Z.
I actually have no idea at all after this step please help me!!
            
        OAZ line on top horizontal
OXB line vertical under O
BYA line diagonal from B to A to form a triangle which is OBA
In the middle of O and B there is a line to show x which is nearer to B.
In the middle of line BA there i s a line to sow Y in the middle.
Question:
OAB is a triangle.
A is the midpoint of OZ.
Y is the midpoint of AB.
X is a point on OB.
(Arrow on top of OA)OA=a
(Arrow on top of OX) OX=2b
(Arrow on top of XB) XB=b
Prove that XYZ is a straight line.
My working out:
1) I drew a line from X to Y to Z.
I actually have no idea at all after this step please help me!!
Answers
                    Answered by
            supersupersuper
            
    Does anyone know? Please help!!
    
                    Answered by
            supersupersuper
            
    anyone? please help!!
    
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