Asked by supersupersuper
the diagram shows a piece of wood in the shape of a cuboid.
diagram: 3cm width, 20cm length, 1.2m for the volume of cuboid
The piece of wood is 3cm by 20cm by 1.2m.
The mass of wood will float in sea water if the density of the wood is less than the density of the sea water.
In a large pool, 1 litre of sea water has a mass of 1030g.
Will the piece of wood float in this pool?
You Must show how you get your answer. (4 marks worth)
My work:
1 m = 100cm
1.2m= 120cm
3 times 20 times 120 = 7200cm3
which is the volume of the cuboid
diagram: 3cm width, 20cm length, 1.2m for the volume of cuboid
The piece of wood is 3cm by 20cm by 1.2m.
The mass of wood will float in sea water if the density of the wood is less than the density of the sea water.
In a large pool, 1 litre of sea water has a mass of 1030g.
Will the piece of wood float in this pool?
You Must show how you get your answer. (4 marks worth)
My work:
1 m = 100cm
1.2m= 120cm
3 times 20 times 120 = 7200cm3
which is the volume of the cuboid
Answers
Answered by
supersupersuper
Anyone know? Please help!
Answered by
natalie
vol of wood= 3*20*120=7200cm3
density of wood= M/V=8000/7200=1.111g/cm3
density of water=1030/1000cm3=1.03g/cm3
so no the wood will not float as it has more density then water
density of wood= M/V=8000/7200=1.111g/cm3
density of water=1030/1000cm3=1.03g/cm3
so no the wood will not float as it has more density then water
Answered by
tara
what's the volume of the water though?
Answered by
Anonymous
1 litre = 1000cm3 which is the volume of the water,
density of pool is 1030g/1000cm3 to get 1.03g/cm3
density of pool is 1030g/1000cm3 to get 1.03g/cm3
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