Asked by Zulaiykherh
Solve the simultaneous equation
P^2-Q^2=40
Q+P=10
Using the substitution method
P^2-Q^2=40
Q+P=10
Using the substitution method
Answers
Answered by
Steve
Q = 10-P
so,
P^2-Q^2 = 40
P^2-(10-P)^2 = 40
20P-100 = 40
20P = 140
P = 7
So, Q = 3
check: 7^2-3^2 = 49-9 = 40
so,
P^2-Q^2 = 40
P^2-(10-P)^2 = 40
20P-100 = 40
20P = 140
P = 7
So, Q = 3
check: 7^2-3^2 = 49-9 = 40
Answered by
Zulaiykherh
Thanks for your support steve
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