Question

Solve the simultaneous equation
P^2-Q^2=40
Q+P=10
Using the substitution method

Answer 1

Q = 10-P

so,

P^2-Q^2 = 40
P^2-(10-P)^2 = 40
20P-100 = 40
20P = 140
P = 7
So, Q = 3

check: 7^2-3^2 = 49-9 = 40

Answer 2

Thanks for your support steve