Asked by Larry
A hemispherical bowl has an external radius of 18cm and is made of wood 3m thick. calculate the volume of the wood in the bowl.
Answers
Answered by
MathMate
For a (complete) sphere,
volume=(4/3)πr³
The volume of material is the volume of whole sphere (radius r2) minus the volume of empty spherical space (radius r1). The thickness t is the difference between r1 and r2, i.e.
r1+t=r2.
Vm=(4/3)π(r2³-r1³)
The volume of material for a hemisphere is half of that of the whole sphere.
volume=(4/3)πr³
The volume of material is the volume of whole sphere (radius r2) minus the volume of empty spherical space (radius r1). The thickness t is the difference between r1 and r2, i.e.
r1+t=r2.
Vm=(4/3)π(r2³-r1³)
The volume of material for a hemisphere is half of that of the whole sphere.
Answered by
Odey vuctoria
It good
Answered by
Anonymous
A hemisphere bowl has an external radius of 18 cm and is made of wood 3cm thick