Asked by Mycah
integral of (dx/(coth^2(2x)*sinh^2(2x))
help, thanksss
help, thanksss
Answers
Answered by
Steve
coth * sinh = cosh
so your integral is just
1/cosh^2(2x) dx = sech^2(2x) dx
That's just a standard form (almost).
so your integral is just
1/cosh^2(2x) dx = sech^2(2x) dx
That's just a standard form (almost).
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