Asked by Anneliese

How do I completely factor this expression?

256z^2 -4 -192z^2 +3

I appreciate your help.
Answered by Damon
64 z^2 - 1

That is the difference of two squares
remember
a^2-b^2 = (a-b)(a+b)
so
(8z-1)(8z+1)
Answered by Steve
256z^2 -4 -192z^2 +3
= (256z^2-4) - 3(64z^2-1)
= (16z-2)(16z+2)-3(8z-1)(8z+1)
= 4(8z-1)(8z+1)-3(8z-1)(8z+1)
= (8z-1)(8z+1)

cool, eh?
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