Asked by ...
the velocity of a chemical reaction is given by dx/dx=k(a-x) where x is the amount transfered in time t,k is a constant and a is the condition at time t=0 when c=0 solve the equation and determine x in terms of t?
Plz show work plz plz
Plz show work plz plz
Answers
Answered by
Damon
I think you might mean
dx/dt = k(a-x)
but what is c?
dx/dt = k(a-x)
but what is c?
Answered by
...
yes sir plz help
Answered by
Steve
just keep on ...
dx/dt = k(a-x)
dx/(a-x) = kt
ln(a-x) = kt^2/2 or, using a new k
ln(a-x) = kt^2
a-x = e^(kt^2)
Now use your initial conditions to find a and k.
dx/dt = k(a-x)
dx/(a-x) = kt
ln(a-x) = kt^2/2 or, using a new k
ln(a-x) = kt^2
a-x = e^(kt^2)
Now use your initial conditions to find a and k.
Answered by
Damon
I am still not sure it is right
maybe
dx/dt = k(a-t) ??
if so try
x = c + p t - kt^2/2
then
dx/dt = p -kt
then p = ka and if c = 0 then
dx/dt = 0 +ka -kt = k(a-t)
so then
x = ka t - k t^2/2
maybe
dx/dt = k(a-t) ??
if so try
x = c + p t - kt^2/2
then
dx/dt = p -kt
then p = ka and if c = 0 then
dx/dt = 0 +ka -kt = k(a-t)
so then
x = ka t - k t^2/2
Answered by
Damon
Use Steve's solution if no typos in problem statement.
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