the velocity of a chemical reaction is given by dx/dx=k(a-x) where x is the amount transfered in time t,k is a constant and a is the condition at time t=0 when c=0 solve the equation and determine x in terms of t?

Plz show work plz plz

5 answers

I think you might mean
dx/dt = k(a-x)
but what is c?
yes sir plz help
just keep on ...

dx/dt = k(a-x)
dx/(a-x) = kt
ln(a-x) = kt^2/2 or, using a new k
ln(a-x) = kt^2
a-x = e^(kt^2)

Now use your initial conditions to find a and k.
I am still not sure it is right
maybe
dx/dt = k(a-t) ??

if so try
x = c + p t - kt^2/2
then
dx/dt = p -kt
then p = ka and if c = 0 then
dx/dt = 0 +ka -kt = k(a-t)
so then
x = ka t - k t^2/2
Use Steve's solution if no typos in problem statement.