Asked by richard
dy/dx - y/x = 0
I got 1/x, but I am not sure if this is right or not.
I got 1/x, but I am not sure if this is right or not.
Answers
Answered by
Steve
well, did you try it?
d/dx (y/x) = 1/x y' - y/x^2
so, now you have an exact differential, which is what you wanted.
d/dx (y/x) = 1/x y' - y/x^2
so, now you have an exact differential, which is what you wanted.
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