Asked by Regina
justify the last two steps of the proof.
Given: ABCD is a parallelogram.
Prove: triangleABC = triangleCDA
1. ABDC is a parallelogram 1. given
2. AB = DC and BC =DC 2. opposite sides of a parallelogram are congruent
3. AC = CA 3. ?
4. triangleABC = triangleCDA 4.?
last two are 3 and 4. g
Given: ABCD is a parallelogram.
Prove: triangleABC = triangleCDA
1. ABDC is a parallelogram 1. given
2. AB = DC and BC =DC 2. opposite sides of a parallelogram are congruent
3. AC = CA 3. ?
4. triangleABC = triangleCDA 4.?
last two are 3 and 4. g
Answers
Answered by
MathMate
hint:
http://study.com/academy/lesson/reflexive-property-of-congruence-definition-examples.html
http://study.com/academy/lesson/reflexive-property-of-congruence-definition-examples.html
Answered by
Anonymous
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Answered by
SherryKnows
@MathMate that doesn't help. im not signing up
Answered by
SherryKnows
like seriously tho, there's got to be teachers in disguise as a student to not let students know the answer. yikesss
Answered by
screw this
D. Reflexive Property of SSS
Answered by
Bob ross
@SherryKnows i wouldnt be suprized
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