power= mc*deltatemp/time
tme= mc*deltaTemp/power
= 2kg*4.18kJ/kgC*80C/(1200watts*.8)
time will be in seconds.
We use an electric immersion heater to heat 2,0 liters water having temperature of 20C to the boiling
point. Specific heat capacity of water is 4,19 kJ/(kg c). The power of the heater is 1,50 kW and efficiency
of heating is 80 %. How much time does the heating take?
1 answer
1 answer