Question

We use an electric immersion heater to heat 2,0 liters water having temperature of 20C to the boiling
point. Specific heat capacity of water is 4,19 kJ/(kg c). The power of the heater is 1,50 kW and efficiency
of heating is 80 %. How much time does the heating take?

Answer 1

power= mc*deltatemp/time

tme= mc*deltaTemp/power
= 2kg*4.18kJ/kgC*80C/(1200watts*.8)

time will be in seconds.