Asked by karem
We use an electric immersion heater to heat 2,0 liters water having temperature of 20C to the boiling
point. Specific heat capacity of water is 4,19 kJ/(kg c). The power of the heater is 1,50 kW and efficiency
of heating is 80 %. How much time does the heating take?
point. Specific heat capacity of water is 4,19 kJ/(kg c). The power of the heater is 1,50 kW and efficiency
of heating is 80 %. How much time does the heating take?
Answers
Answered by
bobpursley
power= mc*deltatemp/time
tme= mc*deltaTemp/power
= 2kg*4.18kJ/kgC*80C/(1200watts*.8)
time will be in seconds.
tme= mc*deltaTemp/power
= 2kg*4.18kJ/kgC*80C/(1200watts*.8)
time will be in seconds.
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