1. P = E*I= 2500.
230I = 2500, I = 10.9A.
2. R = E/I.
3. T = 365 * 15/60 = 91.25 h/yr.
4. Energy = kW * h = 2.5 * 91.25 = 228.125 kWh.
An electric heater of power 2500 W is connected to a voltage of 230 V.
i) Calculate the electric current going through the heater.
ii) What is the resistance of the heater?
iii) How much energy does it consume in a year, if it is switched on 15 min every day.
iv) How much it costs per year to use the heater when the price of electricity is 0,0479 €/kWh?
2 answers
Cost = 0.0479/kW * 228.125kWh =
0 answers