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A scientist needs 80 liters of a 30% acid solution. He currently has a 20% solution and a 60% solution. How many liters of each does he need to make the needed 80 liters of 30% acid solution?
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Answered by
Steve
If he uses x liters of 20%, then the rest (80-x) must be 60%. Now just look at the amounts of acid present:
.20x + .60(80-x) = .30*80
.20x + .60(80-x) = .30*80
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