Asked by Anonymous
What mass (in grams) of CaCl2(s) must be dissolved in pure water at 10.0 deg Celsius to make a 26.4 mL solution and to increase the solution temperature to 16.4 deg Celsius? Assume that there is no heat loss from the solution and that the solution has the same physical properties as pure water.
Data:
DHsol(CaCl2)(s)) = - 82.8 kJ.mol-1
specific heat of water = 4.184 J.g-1.deg-1
density of water = 1.00 g.cm-3
molar mass of CaCl2 = 111 g/mol
Data:
DHsol(CaCl2)(s)) = - 82.8 kJ.mol-1
specific heat of water = 4.184 J.g-1.deg-1
density of water = 1.00 g.cm-3
molar mass of CaCl2 = 111 g/mol
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