Asked by Ree
fâ‚(x) = √(5-x) - 2x^2+2x-4 ; x<1
fâ‚‚(x) = [ 2x - 1 + ln(x) ] / (x - 25) ; x>1
f₃(x) = -1/24 ; x=0
fâ‚‚(x) = [ 2x - 1 + ln(x) ] / (x - 25) ; x>1
f₃(x) = -1/24 ; x=0
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Answered by
Joe
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