Asked by Hannah
An exterior angle of an isosceles triangle has measure 150°. Find two possible sets of measures for the angles of the triangle.
If the exterior angle of the bases is 150°, then the measure of the angle of each base is
_° and the measure of the vertex is
_°.
If the exterior angle of the vertex is 150°, then the measure of the angle of each base is
_° and the measure of the vertex is
_°.
If the exterior angle of the bases is 150°, then the measure of the angle of each base is
_° and the measure of the vertex is
_°.
If the exterior angle of the vertex is 150°, then the measure of the angle of each base is
_° and the measure of the vertex is
_°.
Answers
Answered by
Steve
exterior + interior = 180
The interior angle could be either
the vertex angle
or one of the two base angles
The interior angle could be either
the vertex angle
or one of the two base angles
Answered by
Joe
Ext.Ang.Bases = 150
Int.Ang.Bases = 180-150 = 30 each
For whole triangle: 30+30+x = 180
Int.Ang.Vrtx. = x = 120
Ext.Ang.Vrtx. = 150
Int.Ang.Vrtx. = 180 - 150 = 30
Int.Ang.Bases = 180 - 30 = 150
Base angles are 0.5×150 = 75 each
Int.Ang.Bases = 180-150 = 30 each
For whole triangle: 30+30+x = 180
Int.Ang.Vrtx. = x = 120
Ext.Ang.Vrtx. = 150
Int.Ang.Vrtx. = 180 - 150 = 30
Int.Ang.Bases = 180 - 30 = 150
Base angles are 0.5×150 = 75 each
Answered by
Anonymous
If the exterior angle of the bases is 160degrees, then the measure of the angle of each base is
nothingdegrees and the measure of the vertex is
nothingdegrees.
nothingdegrees and the measure of the vertex is
nothingdegrees.
Answered by
Annonymous num. 2
An exterior angle of an isosceles triangle has measure 110degrees. Find two possible sets of measures for the angles of the triangle.
Answered by
fred
noooo
Answered by
Anonymous
An exterior angle of an isosceles triangle has measure 130 . Find two possible sets of measures for the angles of the triangle
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