Asked by hassan
                hey can someone help me with these i need help 
Consider the curve given by x2 + sin(xy) + 3y2 = C, where C is a constant. The point (1, 1) lies on this curve. Use the tangent line approximation to approximate the y-coordinate when x = 1.01.
Question 19 options:
	
0.996
	
1
	
1.004
	
Cannot be determined
	
1.388
The volume of an open-topped box with a square base is 245 cubic centimeters. Find the height, in centimeters, of the box that uses the least amount of material.
	
7.883 centimeters
	
6 centimeters
	
3.942 centimeters
	
3 centimeters
	
2 centimeters
            
            
        Consider the curve given by x2 + sin(xy) + 3y2 = C, where C is a constant. The point (1, 1) lies on this curve. Use the tangent line approximation to approximate the y-coordinate when x = 1.01.
Question 19 options:
0.996
1
1.004
Cannot be determined
1.388
The volume of an open-topped box with a square base is 245 cubic centimeters. Find the height, in centimeters, of the box that uses the least amount of material.
7.883 centimeters
6 centimeters
3.942 centimeters
3 centimeters
2 centimeters
Answers
                    Answered by
            bobpursley
            
    x2 + sin(xy) + 3y2 = C
solve for dy/dx
2x+cos(xy)xdy/dx+6ydy/dx=0
dy = -2x/(cos(xy)x+6y) * dx
dy= -2*1/(cos(1*1) + 6) dx
but dx= .001
then dy= -.02/(.540+6)= -0.00305810398
so y= 1-dy= 0.996941896
 
    
solve for dy/dx
2x+cos(xy)xdy/dx+6ydy/dx=0
dy = -2x/(cos(xy)x+6y) * dx
dy= -2*1/(cos(1*1) + 6) dx
but dx= .001
then dy= -.02/(.540+6)= -0.00305810398
so y= 1-dy= 0.996941896
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