Asked by sally
Can you check my answers?
1.Use the Binomial Theorem to expand and simplify the expression.
(2 - 3x)3
-27x3 + 104x2 - 36x + 8
-27x3 + 54x2 - 36x + 8
-27x3 + 8
-27x3 + 54x2 - 18x + 8
answer:b
2.Find the 5th term in the expansion of the binomial.
(2x - 4)8
-458,752x3
286,720x4
458,752x3
35,840x4
answer: c
3.Find the 3rd term in the expansion of the binomial.
(x - 2y)12
264x10y2
1760x9y3
-264x10y2
-1760x9y3
answer: d
4.Find the coefficient of the term x2y6 in the binomial expansion of the expression (3x - 2y)8.
81,648
16,128
-81,648
-16,128
answer:c
1.Use the Binomial Theorem to expand and simplify the expression.
(2 - 3x)3
-27x3 + 104x2 - 36x + 8
-27x3 + 54x2 - 36x + 8
-27x3 + 8
-27x3 + 54x2 - 18x + 8
answer:b
2.Find the 5th term in the expansion of the binomial.
(2x - 4)8
-458,752x3
286,720x4
458,752x3
35,840x4
answer: c
3.Find the 3rd term in the expansion of the binomial.
(x - 2y)12
264x10y2
1760x9y3
-264x10y2
-1760x9y3
answer: d
4.Find the coefficient of the term x2y6 in the binomial expansion of the expression (3x - 2y)8.
81,648
16,128
-81,648
-16,128
answer:c
Answers
Answered by
Steve
#1 ok
#2 will be the x^4 term
#3 will be the x^10 y^2 term
#4 Nope. It is
8C6 (3x)^2 (-2y)^6
= 28*3^2*2^6 x^2y^6
= 16128 x^2y^6
#2 will be the x^4 term
#3 will be the x^10 y^2 term
#4 Nope. It is
8C6 (3x)^2 (-2y)^6
= 28*3^2*2^6 x^2y^6
= 16128 x^2y^6
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