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Asked by Lauren

use implicit differentiation to show: d/dx(tan^-1x)=1/(x^2+1)
8 years ago

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Answered by Steve
y = arctan(x)
tan(y) = x
sec^2(y) y' = 1
y' = 1/sec^2(y) = 1/(1+tan^2(y)) = 1/(1+x^2)
8 years ago
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use implicit differentiation to show: d/dx(tan^-1x)=1/(x^2+1)

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