Asked by Marty
If you are blowing up a balloon at a rate of 3 cubic ft per min, what is the rate of change of the radius after 30 seconds
Answers
Answered by
Damon
dV/dt = 3ft^3/min(1 min/60s) = .05 ft^3/s
so
V = .05 * 30 = 1.5 ft^3 at 30 s
V = (4/3) pi r^3
so r = 0.71 ft at 30 s
dV/dr = 4 pi r^2 (the surface area of course)
but
dV/dt = dV/dr * dr/dt
so
dr/dt = dV/dt / (4 pi r^2)
dr/dt = .05 /(4 pi*.71^2)
= .00789 feet/second
so
V = .05 * 30 = 1.5 ft^3 at 30 s
V = (4/3) pi r^3
so r = 0.71 ft at 30 s
dV/dr = 4 pi r^2 (the surface area of course)
but
dV/dt = dV/dr * dr/dt
so
dr/dt = dV/dt / (4 pi r^2)
dr/dt = .05 /(4 pi*.71^2)
= .00789 feet/second
Answered by
Marty
aren't you supposed to plug everything in AFTER you derive it?
Answered by
Damon
LOL, either way
I do physics, I find t easier to visualize step by step.
I do physics, I find t easier to visualize step by step.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.