Asked by Logan
A book cover has the length and width(in inches) shown in the diagram.
A) Find the values of a and b
B) Find the perimeter of the book cover.
Widths are top--3b in. bottom--(2+a)in.
Lengths are left--(3a-b) in. And right--(2+a+2b) in.
A) Find the values of a and b
B) Find the perimeter of the book cover.
Widths are top--3b in. bottom--(2+a)in.
Lengths are left--(3a-b) in. And right--(2+a+2b) in.
Answers
Answered by
Steve
as you know, perimeter is 2(length+width)
With no actual numbers provided, it is impossible to assign values to a and b.
With no actual numbers provided, it is impossible to assign values to a and b.
Answered by
MathMate
"Widths are top--3b in. bottom--(2+a)in."
⇒
3b=2+a
"Lengths are left--(3a-b) in. And right--(2+a+2b) in."
⇒
3a-b=2+a+2b
Solve for a and b, hence perimeter.
Hint: both a and b are positive, and are both integers.
⇒
3b=2+a
"Lengths are left--(3a-b) in. And right--(2+a+2b) in."
⇒
3a-b=2+a+2b
Solve for a and b, hence perimeter.
Hint: both a and b are positive, and are both integers.
Answered by
Steve
You have your two equations.
3b = 2+a
3a-b = 2+a+2b
rearrange things a bit and you have
a - 3b = -2
2a - 3b = 2
subtract and you have
a=4
so, b=2
3b = 2+a
3a-b = 2+a+2b
rearrange things a bit and you have
a - 3b = -2
2a - 3b = 2
subtract and you have
a=4
so, b=2
Answered by
Justice
game on
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