Asked by Carly
The air pressure at sea level is generally about 1013 hPa (hectoPascals). For every kilometer that you go up in elevation, the air pressure decreases by 12%. Write an equation that describes the air pressure when the elevation is x kilmoeters above the sea level.
The answer is y = 1013(0.88)^x
The 0.88 is from the 12% (100% - 12% is 88% which is .88 as a decimal)
My question is: how do I know, just by reading this, that it is exponential? Is it because of the multiplication of the .88? Because exponential is multiplication and linear is addition of the same constant amount?
Thank you.
The answer is y = 1013(0.88)^x
The 0.88 is from the 12% (100% - 12% is 88% which is .88 as a decimal)
My question is: how do I know, just by reading this, that it is exponential? Is it because of the multiplication of the .88? Because exponential is multiplication and linear is addition of the same constant amount?
Thank you.
Answers
Answered by
Reiny
Yes, it would be because of the repeated multiplication by .88
suppose we show a few steps
after 1 km : Pr = 1013(.88)
after 2 km : Pr = 1013(.88)(.88) = 1013 (.88)^2
after 3 km : Pr = 1013(.88)^2 (.88) = 1013 (.88)^3
etc , for
after x km : Pr = 1013 (.88)^x
suppose we show a few steps
after 1 km : Pr = 1013(.88)
after 2 km : Pr = 1013(.88)(.88) = 1013 (.88)^2
after 3 km : Pr = 1013(.88)^2 (.88) = 1013 (.88)^3
etc , for
after x km : Pr = 1013 (.88)^x
Answered by
Carly
Thank you.
Answered by
Reiny
You are welcome
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