Question
Arock weighs 1000N in air and 609N in water.Find its volume.
Answers
lil help
1. Apply equilibrium to the rock when it is submerged in water.
2. Solve the equation from step 1 for volume
1. Equilibrium:
{Force to hold rock stationary in water (apparent weight)}+ {Buoyant Force on rock} = {Weight of rock in air ¾}
V=1000N-609N/9810N/m^3=0.0399 m^3
V=39.9L
2. Solve the equation from step 1 for volume
1. Equilibrium:
{Force to hold rock stationary in water (apparent weight)}+ {Buoyant Force on rock} = {Weight of rock in air ¾}
V=1000N-609N/9810N/m^3=0.0399 m^3
V=39.9L
lil help
1. Apply equilibrium to the rock when it is submerged in water.
2. Solve the equation from step 1 for volume
1. Equilibrium:
{Force to hold rock stationary in water (apparent weight)}+ {Buoyant Force on rock} = {Weight of rock in air}
V=1000N-609N/9810N/m^3=0.0399 m^3
V=39.9L
Sorry there is no 3/4
2. Solve the equation from step 1 for volume
1. Equilibrium:
{Force to hold rock stationary in water (apparent weight)}+ {Buoyant Force on rock} = {Weight of rock in air}
V=1000N-609N/9810N/m^3=0.0399 m^3
V=39.9L
Sorry there is no 3/4