Find the standard form of the equation of the hyperbola with vertices (0±3) and asymptotes (y=±3/2x)

1 answer

form y = (3/2)x
b:a = 3/2, but a = 3
b/3 = 3/2
2b = 9
b = 9/2

hyperbola:
x^2 /9 - y^2/(81/4) = 1
or
x^2/9 - 4y^2/81 = 1
or
9x^2 - 4y^2 = 81

whichever form your text considers standard form