Question
Suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model. A sample of 1000
bacteria selected from this population reached the size of 1274
bacteria in five hours. Find the hourly growth rate parameter.
Note: This is a continuous exponential growth model.
Write your answer as a percentage. Do not round any intermediate computations, and round your percentage to the nearest hundredth.
bacteria selected from this population reached the size of 1274
bacteria in five hours. Find the hourly growth rate parameter.
Note: This is a continuous exponential growth model.
Write your answer as a percentage. Do not round any intermediate computations, and round your percentage to the nearest hundredth.
Answers
Reiny
1000 e^(kt) = 1274
e^(5k) = 1.274
take ln of both sides
5k = ln 1.274
k = ln 1.274/5
= .048323...
= 4.83 % rounded to the nearest hundreth
e^(5k) = 1.274
take ln of both sides
5k = ln 1.274
k = ln 1.274/5
= .048323...
= 4.83 % rounded to the nearest hundreth