Asked by Sam
A rectangular box has a perimeter of 50 inches. Find the length and width of the box that would give the maximum area. Find the maximum possible area of the box.
Answers
Answered by
Damon
square :)
side = 50/4 = 25/2
A = x y
P = 2x+2y = 50
so y = (25-x)
A = x(25-x) = 25 x - x^2
x^2 -25 x = -A
x^2 - 25 x + (25/2)^2 = -A + 625/4
x = 25/2 sure enough so y = 25/2
and A = 625/4 = (25/2)^2
side = 50/4 = 25/2
A = x y
P = 2x+2y = 50
so y = (25-x)
A = x(25-x) = 25 x - x^2
x^2 -25 x = -A
x^2 - 25 x + (25/2)^2 = -A + 625/4
x = 25/2 sure enough so y = 25/2
and A = 625/4 = (25/2)^2
Answered by
a random person
I'm random.
I think the answer is 12.5 inches but this problem is probably way harder than I thought lol
I think the answer is 12.5 inches but this problem is probably way harder than I thought lol
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