Asked by warnar
1.2.3.+2.3.5+3.4.7+...to n terms.
Answers
Answered by
Steve
time to do some thinking, using what you already know. Your sum is
∑k(k+1)(2k+1) = 2k^3 + 3k^2 + k
= 2∑k^3 + 3∑k^2 + ∑k
These are just special sums whose formulas you already know.
∑k(k+1)(2k+1) = 2k^3 + 3k^2 + k
= 2∑k^3 + 3∑k^2 + ∑k
These are just special sums whose formulas you already know.
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