Asked by Anonymous

Name two ways to solve for y=2x^2+16
Answered by Steve
complete the square
quadratic formula
Answered by Anonymous
After it says choose the correct solution(s)
x=-8
x= plus or minus square root of 8
x= plus or minus2isquareroot of 2
x= plus or minus8i
Answered by Steve
so, did you apply one of the methods?

recall that

(a+bi)(a-bi) = a^2+b^2
Answered by Anonymous
HOw do i apply quadratic if there isnt a b
Answered by Steve
there is always a b. In this case, it is zero!

2x^2+16 = 0
2(x^2+8) = 0
2(x+√8 i)(x-√8 i) = 0
...
Answered by Anonymous
I got 4i square root of 8 over 4

So is the answer c
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