Asked by Philip
The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain river normally flows at a speed of 2 miles per hour. What must its speed be in order to transport particles that are 15 times as massive as usual? Round your answer to the nearest hundredth.
Answers
Answered by
Steve
m = ks^6
m/s^6 = k a constant
If m is replaced with 15m, then you want a new s such that
15m/s^6 = m/2^6
s^6 = 15*2^6
s = 2*15^(1/6) = 3.14 mi/hr
m/s^6 = k a constant
If m is replaced with 15m, then you want a new s such that
15m/s^6 = m/2^6
s^6 = 15*2^6
s = 2*15^(1/6) = 3.14 mi/hr
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