Question
Can someone (preferably one of the long-term tutors) check my answers:
Researchers trap 23 devils, and find that 18 of them are infected. Provide an estimate of disease prevalence.
p-hat = (18/23)=0.783
Part II: assuming the same disease prevalence from above.
If they trap 2 devils, what’s the probability that they will get an appropriate pair (i.e. one uninfected female and one uninfected male)?
I used Combinatorics:
23 total, 18 infected and 5 uninfected
Prevalence: 0.783
5C2/23C2 = 10/253 = 0.0395
(0.0395)(.783) = .0309 or 3.1%
Just need to make sure I'm on the right track. Thanks for your help.
Researchers trap 23 devils, and find that 18 of them are infected. Provide an estimate of disease prevalence.
p-hat = (18/23)=0.783
Part II: assuming the same disease prevalence from above.
If they trap 2 devils, what’s the probability that they will get an appropriate pair (i.e. one uninfected female and one uninfected male)?
I used Combinatorics:
23 total, 18 infected and 5 uninfected
Prevalence: 0.783
5C2/23C2 = 10/253 = 0.0395
(0.0395)(.783) = .0309 or 3.1%
Just need to make sure I'm on the right track. Thanks for your help.
Answers
Jeremy
Forgot to add that the sex ratio is even and both have the same prevalence.