Asked by Subiza
What volume of 0.900 M HCl is required to complete neutralize 50.0 ml of a 0.500 M Ba(OH)2 solution?
Answers
Answered by
bobpursley
balance the equation. You will see that it takes two moles of HCl for each mole of Ba(OH)2
2molesHCl=1moleBa(OH)2
2*.9*Va=1*.5*50ml
solve for volume of acid, Va
2molesHCl=1moleBa(OH)2
2*.9*Va=1*.5*50ml
solve for volume of acid, Va
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