The sum of 3 integers is 194. the sum of the first and second integers exceeds the third by 80. The third integer is 45 less than the first. Find the three integers

Answer 1

let the first be x
let the second be y
the third is x-45

x+y > x-45 by 80 ---> x+y = x-45 + 80
x + y = x + 35
y = 35

x + y + x-45 = 194
2x + 35 - 45 = 194
2x = 204
x = 102

the first is 102
the 2nd is 35
the 3rd is 57