Asked by KT
A trough is 15 ft long and 4 ft across the top. Its ends are isosceles triangles with height 3 ft. Water runs into the trough at the rate of 2.5 ft3/min. How fast is the water level rising when it is 0.89 ft deep? Give your answer correct to 3 decimal places.
Answers
Answered by
Steve
when the water has depth y, the surface has with 4/3 y. That means the volume is
v = y(4/3 y)/2 * 15 = 10y^2
dv/dt = 20y dy/dt
Now just plug in your numbers to find dy/dt
v = y(4/3 y)/2 * 15 = 10y^2
dv/dt = 20y dy/dt
Now just plug in your numbers to find dy/dt
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