Asked by FEMI

what volume of hydrogen is produced with excess HCL according to the equation Zn+2HCL-ZnCL2+H2
Answered by FEMI
from the equation 65g of Zn produced 22.4dm3 of H2 :36.5g of Zn=36.5g*22.4dm3/65=12.6dm3
Answered by DrBob222
The volume of H2 depends upon how much Zn you started with. You don't have that in the problem.
There are no AI answers yet. The ability to request AI answers is coming soon!