what volume of hydrogen is produced with excess HCL according to the equation Zn+2HCL-ZnCL2+H2
2 answers
from the equation 65g of Zn produced 22.4dm3 of H2 :36.5g of Zn=36.5g*22.4dm3/65=12.6dm3
The volume of H2 depends upon how much Zn you started with. You don't have that in the problem.