(0.08b^{4m+8})\div (18b^{m−2})

Question

this broil confuses me, can u guys plz show how its solved but not give me the answer

Answer 1

1\frac{1}{5}m^{4−n}·0.5m^{n−6}
this one also stumped me i can't find any way to solve it can you guys show me how to do it and give me the answer it would be real help! :)

Answer 2

I don't know what you mean by "solve" it. It's just an expression. No equation.

(0.08b^{4m+8})/(18b^{m−2})
= .08/18 b^(4m+8-(m-2))
= 1/225 b^(3m+10)

1/(1/5) m^(4-n) * 1/2 m^(n-6)
= 5/(2m^2)

Answer 3

sorry i meant to just show how its supposed to be soled

Answer 4

i meant simplify

Answer 5

for the first one is it
1/2b