Asked by Adil
The internal angles of a triangle in the ratio 3:5:7. Find the degree measures of the angles. Also find measure of its greatest exterior angle.Give complete calculation.
Answers
Answered by
Reiny
let the angles be 3x, 5x, and 7x
you know they have to add up to 180°
Solve
3x + 5x + 7x = 180 for x, the sub back into my definitions.
you know they have to add up to 180°
Solve
3x + 5x + 7x = 180 for x, the sub back into my definitions.
Answered by
Bosnian
Let 3x be the smallest angle; this will make other angles 5x and 7x.
There are 180° in a triangle, so:
3 x + 5 x + 7 x = 180 °
15 x =180° Divide both sides by 15
x = 180° / 15
x = 12 °
Angles:
3 x = 3 * 12 = 36°
5 x = 5 * 12 = 60°
7 x = 7 * 12 = 84°
Proof:
36° / 84° = 4 * 3 * 3 / ( 4 * 3 * 7 ) = 3 / 7
60 / 84 = 4 * 3 * 5 / ( 4 * 3 * 7 ) = 5 / 7
There are 180° in a triangle, so:
3 x + 5 x + 7 x = 180 °
15 x =180° Divide both sides by 15
x = 180° / 15
x = 12 °
Angles:
3 x = 3 * 12 = 36°
5 x = 5 * 12 = 60°
7 x = 7 * 12 = 84°
Proof:
36° / 84° = 4 * 3 * 3 / ( 4 * 3 * 7 ) = 3 / 7
60 / 84 = 4 * 3 * 5 / ( 4 * 3 * 7 ) = 5 / 7
Answered by
Jonny
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