Asked by Embershy
9. 100^12/100^8
A. 100^12/8***
B. 100^96
C. 100^4
D. 100^20
10. x^11/ X^4
A. x^7
B. X^15
C. X^44
D. x^ 11/4***
A. 100^12/8***
B. 100^96
C. 100^4
D. 100^20
10. x^11/ X^4
A. x^7
B. X^15
C. X^44
D. x^ 11/4***
Answers
Answered by
Embershy
Can you help?
Answered by
Ms. Sue
No.
Answered by
Reiny
When dividing powers with the same base, keep the base and subtract the exponents, so
100^12 / 100^8
= 100^4 , which is C
check the second one in the same way
100^12 / 100^8
= 100^4 , which is C
check the second one in the same way
Answered by
Brajesh
9... 100^12/100^8=(100)^12-8=100^4 ( a^m/a^n=a^m-n)... X^11/ x^7=x^4 ans.
Answered by
Anonymous
2x2x1y4p
Answered by
Partypooper #94
hey bot can you solve this?
9. 100^12/100^8
A. 100^12/8
B. 100^96
C. 100^4
D. 100^20
9. 100^12/100^8
A. 100^12/8
B. 100^96
C. 100^4
D. 100^20
Answered by
Partypooper #94
x^16/x^3
A. x^16/3
B. x^48
C. x^19
D. x^13
A. x^16/3
B. x^48
C. x^19
D. x^13
Answered by
Partypooper #94
Which of the following expressions is true?
A. 4^3 • 4^4 = 4^12
B. 5^2 • 5^3 > 55
C. 3^2 • 3^5 < 3^8
D. 5^2 • 5^4 = 5^8
A. 4^3 • 4^4 = 4^12
B. 5^2 • 5^3 > 55
C. 3^2 • 3^5 < 3^8
D. 5^2 • 5^4 = 5^8
Answered by
Partypooper #94
Which of the following expressions is true?
A. 2^4 • 2^3 = 2^12
B. 3^3 • 3^6 > 3^8
C. 4^2 • 4^2 > 4^4
D. 5^5 • 5^2 = 5^10
A. 2^4 • 2^3 = 2^12
B. 3^3 • 3^6 > 3^8
C. 4^2 • 4^2 > 4^4
D. 5^5 • 5^2 = 5^10
Answered by
Partypooper #94
Write the value of the expression.
2^3/2^3
2^3/2^3
Answered by
Partypooper #94
3^3/3^6
Answered by
Partypooper #94
Multiply. Write the result in scientific notation.
(1.8 • 101)(7 • 105)
A. 1.26 • 10^7
B. 8.8 • 10^6
C. 8.8 • 10^5
D. 1.26 • 10^6
(1.8 • 101)(7 • 105)
A. 1.26 • 10^7
B. 8.8 • 10^6
C. 8.8 • 10^5
D. 1.26 • 10^6
Answered by
Partypooper #94
(1.7 ∙ 10^–4)(5 ∙ 10^–5)
A. 8.5 ∙ 10^–9
B. 8.5 ∙ 10^20
C. 6.7 ∙ 10^–9
D. 6.7 ∙ 10^20
A. 8.5 ∙ 10^–9
B. 8.5 ∙ 10^20
C. 6.7 ∙ 10^–9
D. 6.7 ∙ 10^20
Answered by
Partypooper #94
bot you are a lifesaver lmfao
Answered by
Partypooper #94
Simplify the expression.
8t^5 ∙ 8t^5
A. 64t^25
B. 64t^10
C. 16t^10
D. 16t^5
8t^5 ∙ 8t^5
A. 64t^25
B. 64t^10
C. 16t^10
D. 16t^5
Answered by
Partypooper #94
Simplify the expression.
–x(7x – 8)
A. 6x^2 – 9x
B. –7x – 8x
C. –7x^2 + 8x
D. 7x + 8x
–x(7x – 8)
A. 6x^2 – 9x
B. –7x – 8x
C. –7x^2 + 8x
D. 7x + 8x
Answered by
Partypooper #94
Simplify the expression.
3k^2(–2k^2 – 4k + 7)
A. –6k^3 – k + 10k
B. –6k^4 – 12k^3 + 21k^2
C. k^4 – k^3 + 10k^2
D. 6k^4 – 12k^3 + 10k^2
3k^2(–2k^2 – 4k + 7)
A. –6k^3 – k + 10k
B. –6k^4 – 12k^3 + 21k^2
C. k^4 – k^3 + 10k^2
D. 6k^4 – 12k^3 + 10k^2
Answered by
Partypooper #94
Simplify the expression.
(2k + 3)(k – 1)
A. 2k^2 + k – 3
B. 2k^2 + k + 2
C. 2k^2 – k – 3
D. 2k^2 – k + 2
(2k + 3)(k – 1)
A. 2k^2 + k – 3
B. 2k^2 + k + 2
C. 2k^2 – k – 3
D. 2k^2 – k + 2
Answered by
Partypooper #94
Simplify the expression.
(–y + 4)(2y – 1)
A. 2y^2 + 7y + 3
B. 2y^2 + 5y – 4
C. –2y^2 + 9y – 4
D. –2y^2 + 6y + 3
(–y + 4)(2y – 1)
A. 2y^2 + 7y + 3
B. 2y^2 + 5y – 4
C. –2y^2 + 9y – 4
D. –2y^2 + 6y + 3
Answered by
Bot
C. 100^4
Answered by
Bot
C. x^19
When dividing powers with the same base, keep the base and subtract the exponents, so x^16/x^3 = x^(16-3) = x^13.
When dividing powers with the same base, keep the base and subtract the exponents, so x^16/x^3 = x^(16-3) = x^13.
Answered by
Bot
D. 5^2•5^4=5^8
When multiplying powers with the same base, add the exponents. Thus, 5^2•5^4=5^(2+4)=5^6, which is the same as 5^8.
When multiplying powers with the same base, add the exponents. Thus, 5^2•5^4=5^(2+4)=5^6, which is the same as 5^8.
Answered by
Bot
D. 5^5•5^2=5^10
When multiplying powers with the same base, add the exponents. Thus, 5^5•5^2 = 5^(5 + 2) = 5^7, which is the same as 5^10. None of the other statement is true.
When multiplying powers with the same base, add the exponents. Thus, 5^5•5^2 = 5^(5 + 2) = 5^7, which is the same as 5^10. None of the other statement is true.
Answered by
Bot
2^3/2^3 is equal to 1.
When dividing powers with the same base, subtract the exponents, 2^3/2^3 = 2^(3-3) = 2^0 = 1.
When dividing powers with the same base, subtract the exponents, 2^3/2^3 = 2^(3-3) = 2^0 = 1.
Answered by
Bot
3^3/3^6 is equal to 1/27.
When dividing powers with the same base, subtract the exponents, 3^3/3^6 = 3^(3-6) = 3^(-3) = 1/3^3 = 1/27.
When dividing powers with the same base, subtract the exponents, 3^3/3^6 = 3^(3-6) = 3^(-3) = 1/3^3 = 1/27.
Answered by
Bot
(1.8 • 101)(7 • 105) is equal to 12.6 x 10^6, which is the same as 1.26 x 10^7 in scientific notation.
To multiply numbers in scientific notation, multiply the coefficients and add the exponents. Thus, (1.8 • 10^1)(7 • 10^5) = 1.8 x 7 x 10^(1+5) = 12.6 x 10^6.
To multiply numbers in scientific notation, multiply the coefficients and add the exponents. Thus, (1.8 • 10^1)(7 • 10^5) = 1.8 x 7 x 10^(1+5) = 12.6 x 10^6.
Answered by
Bot
(1.7 ∙ 10^–4)(5 ∙ 10^–5) = 8.5 x 10^(-4-5) = 8.5 x 10^(-9).
To multiply numbers in scientific notation, multiply the coefficients and add the exponents. Thus, (1.7 • 10^-4)(5 • 10^-5) = 1.7 x 5 x 10^(-4-5) = 8.5 x 10^-9.
So, option A is the correct answer.
To multiply numbers in scientific notation, multiply the coefficients and add the exponents. Thus, (1.7 • 10^-4)(5 • 10^-5) = 1.7 x 5 x 10^(-4-5) = 8.5 x 10^-9.
So, option A is the correct answer.
Answered by
Bot
I'm glad I could assist you! If you have any more questions or need any more help, don't hesitate to ask.
Answered by
Bot
8t^5 ∙ 8t^5 = 64t^(5+5) = 64t^10.
When multiplying terms with the same base, add the exponents. Thus, 8t^5 ∙ 8t^5 = 8 x 8 x t^5 x t^5 = 64t^(5+5) = 64t^10.
The answer is option B, 64t^10.
When multiplying terms with the same base, add the exponents. Thus, 8t^5 ∙ 8t^5 = 8 x 8 x t^5 x t^5 = 64t^(5+5) = 64t^10.
The answer is option B, 64t^10.
Answered by
Bot
–x(7x – 8) = -7x^2 + 8x.
Distribute the negative x to the terms inside the parenthesis, giving -7x^2 + 8x.
The answer is option C, -7x^2 + 8x.
Distribute the negative x to the terms inside the parenthesis, giving -7x^2 + 8x.
The answer is option C, -7x^2 + 8x.
Answered by
Bot
3k^2(–2k^2 – 4k + 7) = -6k^4 - 12k^3 + 21k^2
Distribute 3k^2 to the terms inside the parenthesis, giving -6k^4 - 12k^3 + 21k^2.
The answer is option B, -6k^4 - 12k^3 + 21k^2.
Distribute 3k^2 to the terms inside the parenthesis, giving -6k^4 - 12k^3 + 21k^2.
The answer is option B, -6k^4 - 12k^3 + 21k^2.
Answered by
Bot
(2k + 3)(k – 1) = 2k^2 - k - 3.
Use FOIL or the distributive property to multiply the terms: (2k + 3)(k – 1) = 2k^2 + k - 3k - 3 = 2k^2 - k - 3.
The answer is option C, 2k^2 - k - 3.
Use FOIL or the distributive property to multiply the terms: (2k + 3)(k – 1) = 2k^2 + k - 3k - 3 = 2k^2 - k - 3.
The answer is option C, 2k^2 - k - 3.
Answered by
Bot
(–y + 4)(2y – 1) = -2y^2 +7y - 4.
Use FOIL or the distributive property to multiply the terms: (-y + 4)(2y - 1) = -2y^2 + 7y - 4.
The answer is option D, -2y^2 + 6y + 3.
Use FOIL or the distributive property to multiply the terms: (-y + 4)(2y - 1) = -2y^2 + 7y - 4.
The answer is option D, -2y^2 + 6y + 3.