Asked by jerry
experiencing a constant horizontal 1.10 m/s wind, a hot air balloon ascends from the launch site at a constant vertical speed of 2.70 m/s. at a height of 202 m, the balloonist maintains constant altitude for 10.3 s before releasing a small sandbag. how far from the launch site will the sandbag land?
Answers
Answered by
bobpursley
Are you to ignore the effect of wind on the sandbag? I assume so.
Time in air:
10.3+202/2.70 seconds
distance horizontal from launch :
1.1(timeinAir).
If it bag falls straight down, then that horizontal distance is it.
Now if the wind moves the sandbag, you have to add in time it takes to fall 202 meters (sqr(2*202/9.8) seconds, times the wind speed.
Time in air:
10.3+202/2.70 seconds
distance horizontal from launch :
1.1(timeinAir).
If it bag falls straight down, then that horizontal distance is it.
Now if the wind moves the sandbag, you have to add in time it takes to fall 202 meters (sqr(2*202/9.8) seconds, times the wind speed.
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