Asked by Arisha imtiaz
To what potential a sphere of radius 10cm be charged so that the surface density of charge is equal to 1
Answers
Answered by
Damon
1 what? coulombs/m^2? coulombs/cm^2 ? I will assume m^2 and call it x
area = A = 4 pi r^2
A = 4 pi (r)^2
Q = 1* A
potential= V = k Q/r = Q/(4 pi eo r)
V = 1* 4 pi r^2/(4 pi eo r)
V = r/eo
area = A = 4 pi r^2
A = 4 pi (r)^2
Q = 1* A
potential= V = k Q/r = Q/(4 pi eo r)
V = 1* 4 pi r^2/(4 pi eo r)
V = r/eo
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