Asked by shy
a farmer wants to create pens along side his barn for his chicken ducks and geese. he has 600 ft of fencing and wants to create 2 equal spaces for each species. what is the largest area he could have? Also one side is along a house so no fencing is needed there. the image looks like
box box ho
box box us
box box e
box box ho
box box us
box box e
Answers
Answered by
Damon
3 of length x
1 of length y
A = x y
length of fencing = 3x+y = 600
so y = (600 - 3x)
A = x(600 - 3x) = -3 x^2 + 600 x
dA/dx = -6 x + 600
min or max A when 6 x = 600
or x = 100
then y = 300
A = x y = 30,000 ft^2
or about 3/4 of an acre
1 of length y
A = x y
length of fencing = 3x+y = 600
so y = (600 - 3x)
A = x(600 - 3x) = -3 x^2 + 600 x
dA/dx = -6 x + 600
min or max A when 6 x = 600
or x = 100
then y = 300
A = x y = 30,000 ft^2
or about 3/4 of an acre
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