Question
One of the two equal angles of an isosceles.triangle is greatest than the third angle 18° . Find the three angles of the isosceles triangle
Answers
Bosnian
A = greatest angle
B = smaller angle
A = B + 18°
The sum of the angles in a triangle is 180°
2 A + B = 180°
2 ( B + 18° ) + B = 180°
2 B + 2 * 18° + B = 180°
3 B + 36° = 180° Subtract 36° to both sides
3 B + 36° = 180°
3 B + 36° - 36 ° = 180° - 36°
3 B = 144° Divide both sides by 3
B = 144° / 3
B = 48°
A = B + 18°
A = 48° + 18°
A = 66°
Three angles of the triangle:
66° , 66° , 48°
B = smaller angle
A = B + 18°
The sum of the angles in a triangle is 180°
2 A + B = 180°
2 ( B + 18° ) + B = 180°
2 B + 2 * 18° + B = 180°
3 B + 36° = 180° Subtract 36° to both sides
3 B + 36° = 180°
3 B + 36° - 36 ° = 180° - 36°
3 B = 144° Divide both sides by 3
B = 144° / 3
B = 48°
A = B + 18°
A = 48° + 18°
A = 66°
Three angles of the triangle:
66° , 66° , 48°