Asked by Gang

Quadrilateral EFGH is a rectangle. If EM equals 5X plus one and HF equals 42 find the value of X

Quadrilateral ABCD is a rectangle. Find the value of "x" if m/_DAC=(4x+8)degrees and m/_ CAB=(5x-8) degrees
Answered by Damon
if m is at the center then diagonal = 2(5x+1)
which is the same as the other diagonal 42
5x+1 = 21
5x = 20
x = 4
Answered by Damon
The angles are both in corner A
so they add up to 90 degrees
4x+8 = 5x-8
x = 16
Answered by edgar
how to find angles
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