Asked by Molly
A 100 gallon tank is filled with a salt solution containing 10 lbs of salt. Pure water is pumped in at a rate of 5 gallons per minute and pumped out at the same rate. How many minutes will it take the amount of salt to drop to 8 lbs? Round to one decimal place.
Answers
Answered by
Steve
see the related questions below. They should help you set up and solve your differential equation.
If you get stuck, come back with what you have done so far.
If you get stuck, come back with what you have done so far.
Answered by
Molly
I keep getting an negative answer. I know the answer is 4.5 only because the teacher tells us what it I just cannot figure out how to set it up. I got e^t/20 +1/20Ae^t/20 = 5e^t/20, which is way wrong
Answered by
Steve
check to see how much salt is coming in and going out. Since pure water contains no salt, and the 5 gallons leaving contain 5/100 of the salt present, we have
ds/dt = 5/100 * 0 - 5/100 s
ds/dt = -1/20 s
ds/s = -1/20 dt
s = c*e^(-t/20)
Since s(0) = 10,
s = 10*e^-(t/20)
so, let's find t when s=8
10 e^(-t/20) = 8
e^(-t/20) = 0.8
-t/20 = ln0.8
t = -20 ln0.8 = 4.46
Looks like you need to review the logic that led to your original DE.
ds/dt = 5/100 * 0 - 5/100 s
ds/dt = -1/20 s
ds/s = -1/20 dt
s = c*e^(-t/20)
Since s(0) = 10,
s = 10*e^-(t/20)
so, let's find t when s=8
10 e^(-t/20) = 8
e^(-t/20) = 0.8
-t/20 = ln0.8
t = -20 ln0.8 = 4.46
Looks like you need to review the logic that led to your original DE.
Answered by
Molly
Thanks (:
I knew it had t/20 in the solution somehow. I see what I did wrong now.
I knew it had t/20 in the solution somehow. I see what I did wrong now.
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